2x^2+100x=25200

Solution for 2x^2+100x=25200 equation:

2x^2+100x=25200

We move all terms to the left:

2x^2+100x-(25200)=0

a = 2; b = 100; c = -25200;
Δ = b2-4ac
Δ = 1002-4·2·(-25200)
Δ = 211600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{211600}=460$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-460}{2*2}=\frac{-560}{4}
=-140
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+460}{2*2}=\frac{360}{4}
=90
$